We will use the given array helpers to transform the given for loops away from being for loops.

Here is some data you can use, feel free to add more car objects to it:

const cars = [
    {
       make: "ford",
       model: "E150",
       year: 2000
    },
    {
       make: "chevy",
       model: "malibu",
       year: 2017
    },
    {
       make: "chevy",
       model: "malibu",
       year: 2003
    },
    {
       make: "ford",
       model: "E150",
       year: 1999
    },
    {
       make: "chevy",
       model: "sedan",
       year: 2009
    },
]

Use .forEach() to replace the following for loop.

for (let i = 0; i < cars.length; i++) {
  console.log(`${cars[i].length} goes vroom`);
}

Use .map() to replace the following for loop.

var angryCars = [];

for (let i = 0; i < cars.length; i++) {
  angryCars.push(cars[i].make.toUpperCase());
}

Use .filter() to replace the following for loop.

var newCars = [];

for (let i = 0; i < cars.length; i++) {
  if (cars[i].year > 2005){
    newCars.push(cars[i]);
  }
}

Use .find() to replace the following for loop.

for (let i = 0; i < cars.length; i++) {
  if (cars[i].model === "E150"){
    let coolVan = cars[i];
    break;
  }
}

Use .some() to replace the following for loop.

for (let i = 0; i < cars.length; i++) {
  if (cars[i].model === "E150"){
    console.log("It is true that there is one or more E150s");
    break;
  }
}

Use .every() to replace the following for loop.

for (let i = 0; i < cars.length; i++) {
  if (cars[i].model != "E150"){
    console.log("It is false that every car is an E150");
    break;
  }
}

Use .reduce() to replace the following for loop and carTotals definition.

var numberOfFords = 0;
var numberOfChevys = 0;

for (let i = 0; i < cars.length; i++) {
  if (cars[i].make === "ford"){
    numberOfFords ++;
  }
  if (cars[i].make === "chevy"){
    numberOfchevys ++;
  }
}

let carTotals = { numberOfFords: numberOfFords, numberOfChevys: numberOfChevys }